<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Quantum Learning on Jice Lavocat</title><link>https://jice.lavocat.name/categories/quantum-learning/</link><description>Recent content in Quantum Learning on Jice Lavocat</description><generator>Hugo</generator><language>en-us</language><copyright>All rights reserved - 2016</copyright><lastBuildDate>Wed, 16 Sep 2009 00:00:00 +0000</lastBuildDate><atom:link href="https://jice.lavocat.name/categories/quantum-learning/index.xml" rel="self" type="application/rss+xml"/><item><title>Impatient Learning and sub/sup Majority Problem</title><link>https://jice.lavocat.name/blog/2009/impatient-learning-and-sub/sup-majority-problem/</link><pubDate>Wed, 16 Sep 2009 00:00:00 +0000</pubDate><guid>https://jice.lavocat.name/blog/2009/impatient-learning-and-sub/sup-majority-problem/</guid><description>&lt;p style="text-align: justify;"&gt;
 In this article I present some probabilities of 1-step learning optimized by Impatient Learning (&lt;a href="http://www.citebase.org/abstract?id=oai:arXiv.org:quant-ph/0309059" target="_blank"&gt;http://www.citebase.org/abstract?id=oai:arXiv.org:quant-ph/0309059&lt;/a&gt;) for the sub/sup Majority Learning.
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 The (Sub/Sup) Majority Learning
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 Take a bitstring &lt;em&gt;a&lt;/em&gt;, and an integer $$\theta$$. The oracle will respond 0 if $$d(a,x)\leq \theta$$  if queried with &lt;em&gt;x&lt;/em&gt; and 1 otherwise. In other terms this oracle reply yes if two bitstrings agree on at least $$\theta$$ bit.
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 Here are the probability with a simple membership oracle (used with the usual phase kickback trick). Only even &lt;em&gt;n&lt;/em&gt; gives an invertible matrix for the use of impatient learning.
&lt;/p&gt;</description></item><item><title>Classical algorithm for the Majority Problem</title><link>https://jice.lavocat.name/blog/2009/classical-algorithm-for-the-majority-problem/</link><pubDate>Tue, 07 Jul 2009 00:00:00 +0000</pubDate><guid>https://jice.lavocat.name/blog/2009/classical-algorithm-for-the-majority-problem/</guid><description>&lt;h2 id="presentation-of-the-problem-"&gt;Presentation of the problem :&lt;/h2&gt;
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 The majority problem is equivalent to the perceptron learning. For each $$a \in \mathbb{Z}_n$$ define a function $$m_a : \mathbb{Z}_2^N \rightarrow \mathbb{Z}_2$$ :
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 $$m_a(x)= \begin{cases} 1 &amp; \text{ if } wt(a-x)\leq n/2 \\0 &amp; \text{ otherwise } \end{cases}$$
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 Where wt is the weight of a bit-string (number of 1).
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 Alternatively we can write : $$ m_a(x) = \Theta (n/2 &amp;#8211; wt(x-a) )$$.
&lt;/p&gt;</description></item><item><title>Some papers about Oracle identification</title><link>https://jice.lavocat.name/blog/2009/some-papers-about-oracle-identification/</link><pubDate>Wed, 01 Jul 2009 00:00:00 +0000</pubDate><guid>https://jice.lavocat.name/blog/2009/some-papers-about-oracle-identification/</guid><description>&lt;p&gt;There is a bunch of interesting papers dealing with Oracle Identification.&lt;/p&gt;
&lt;p&gt;Here is a list of the ones I found interesting to read :&lt;/p&gt;</description></item><item><title>Latex on my blog</title><link>https://jice.lavocat.name/blog/2009/latex-on-my-blog/</link><pubDate>Fri, 19 Jun 2009 00:00:00 +0000</pubDate><guid>https://jice.lavocat.name/blog/2009/latex-on-my-blog/</guid><description>&lt;p style="text-align: justify;"&gt;
 WordPress permet d&amp;#8217;inclure du Latex dans ses pages grace a un script hébergé sur ses propres serveur. Voila qui va me rendre heureux tout ca :
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